On the Exponential Diophantine Equation $x^2+(3a^2-1)^m=(4a^2-1)^n$
Received:April 29, 2005  Revised:December 10, 2006
Key Words: exponential Diophantine equations   Lucas sequences   primitive divisors   Kronecker symbol.  
Fund Project:the Natural Science Foundation of Guangdong Province (04009801); the Important Science Research Foundation of Foshan University.
Author NameAffiliation
HU Yong-zhong Department of Mathematics, Foshan University, Guangdong 528000, China 
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Abstract:
      We apply a new, deep theorem of Bilu, Hanrot \& Voutier and some fine results on the representation of the solutions of quadratic Diophantine equations to solve completely the exponential Diophantine equation $x^2+(3a^2-1)^m=(4a^2-1)^n$ when $3a^2-1$ is a prime or a prime power.
Citation:
DOI:10.3770/j.issn:1000-341X.2007.02.003
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